complete Computer Based Numerical Techniques Course

operations of normalized floating point point, . Errors and Floating point Representation Pitfall of floating point Representation, Bisection Method, Regula-Falsi Method, Program of Bisection Method , Algorithm of Bisection Method, Secant Method, Newton-Raphson Method, Gauss Elimination Method, Gauss Seidel Iterative method, Calsulus of finite Differences, Relations b/w the operation, Newton Forward & backward Difference formula, and many more..

Sunday, April 22, 2018

approx. value =0.333 and true value = 1/3, find ea ,er and ep..?

Solution:-

x=0.333    ,    x'=1/3

  e_a= ₁ - _0.333_{× 3}

3 1 × 3

  =0.333 - 0.333

e_a= 0

e_r= 1/3 – 0.333

   1/3

=_0.00033

_1/3

e_r=0.000999

  e_p= 0.000333_{× 100}

_0.333

e_p= 0.09999.

complete Computer Based Numerical Techniques Course

Sunday, April 22, 2018

approx. value =0.333 and true value = 1/3, find ea ,er and ep..?

Solution:-

x=0.333    ,    x'=1/3

  e_a= ₁ - _0.333_{× 3}

3 1 × 3

  =0.333 - 0.333

e_a= 0

e_r= 1/3 – 0.333

   1/3

=_0.00033

_1/3

e_r=0.000999

  e_p= 0.000333_{× 100}

_0.333

e_p= 0.09999.

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Sunday, April 22, 2018

approx. value =0.333 and true value = 1/3, find ea ,er and ep..?

Solution:- x=0.333 , x'=1/3 ea= 1 - 0.333 × 3 3 1 × 3 =0.333 - 0.333 ea= 0 er= 1/3 – 0.333 1/3 =0.00033 1/3 er =0.000999 ep= 0.000333 × 100 0.333 ep= 0.09999.

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Solution:-

x=0.333 , x'=1/3

e_a= ₁ - _0.333_{× 3}

3 1 × 3

=0.333 - 0.333

e_a= 0

e_r= 1/3 – 0.333

1/3

=_0.00033

_1/3

e_r=0.000999

e_p= 0.000333_{× 100}

_0.333

e_p= 0.09999.